Got Those Echoplex Multiply Blues

["Gary Lehmann" <relayonemanband@cts.com>]

Loneliness is replying to your own online postings

> I've just discovered something interesting on the Echoplex that I want to
> share with the other EDP users on this list.  This has to do with the
> multiply function.  What I've discovered is that I can end the multiply
> function by hitting insert and then immediately return to the multiply
> function to generate a blues progression rather elegantly.  However, some
of
> the subsequent behavior is puzzling me, so I want to give this specific
> example.  FYI, I have quantize on.
> The song I am constructing is a blues.  I play a figure for the first
> phrase, the "I" chord, which is one bar in length.  I allow it to play 
>one
> additional time (now playing bar 2).  I hit multiply, and the "song"
begins.
> After the fourth cycle begins and bar 4 of the "song" is playing, I hit
> insert and when bar 5 begins, I am in insert mode and I play the "IV"
chord
> for two bars.  Around bar 6 or so I hit multiply again and when bar 7
> arrives, I am treated to two bars of "I", as created by the original
> multiply.  I allow this to continue through bar 8--I press insert during
bar
> 8, and when bar 9 arrives, I play the "V" chord for two bars, pressing
> multiply during bar 10.  When bar 10 arrives, it again delivers two bars
of
> "I", and during bar 12 I hit either multiply or record.  This completes
the
> "song" in 12 bars.  This is what I discovered.
> Now to the part I don't fully understand.  Let's alter the chord
> progression.  We start with the same figure for the first phrase, the "I"
> chord, which is one bar in length.  I allow it to play one additional 
>time
> (now playing bar 2).  I hit multiply, and the "song" begins.  After the
> second cycle begins and bar 2 of the "song" is playing, I hit insert and
> when bar 3 begins, I am in insert mode and I play the "IV" chord for two
> bars.  Around bar 4 or so I hit multiply again and when bar 5 arrives, I
am
> treated to two bars of "I", as created by the original multiply.  During
bar
> 6, I hit insert and play the "V" chord for two bars (bars 7 and 8).
During
> bar 8 I hit multiply.  When bar 9 arrives, I expect two bars of the "I"
> chord.  Instead I am jarred by one bar of "I" and one bar of "IV".  What
> gives?  Or to put it more clearly--with which cycle does the multiply
begin?

Well Gary, the answer is, cycle two--at least in bars 11 and 12 of the 
first
example.
Gee I wonder why?
G

PS--Viva El Puerco Espanol!