Support |
PERILLE (05:27 AM 08.06.2000) wrote: >Example : 8 playback + 1 recording stereo channels @ 48khz/16bit > >SmartMedia : >- 32 READ bytes*70nsec + 4 RECORD bytes*660nsec = 4.9µsec*48khz = 24% => >PASS > >CompactFlash : >- 36 bytes*660nsec = 23.8µsec*48khz = 114% => CRASH ! Am I correct in seeing you outline a total of 9 stereo tracks here? Repeater is obviously laid out as a 4 track machine which we're _assuming_ to be 4 stereo tracks. I don't think that Damon has said anything about sample rate, but I would be more likely to assume 44.1khz over 48khz. I personally have an easier time looking at the situation by defining the data quantity first and then looking at the bandwidth required. In doing so, I come up with: 1 sample * 16bits/sample = 2 bytes/sample 2 channels/track = 4 bytes/sample/track 4 stereo tracks = 16 bytes/sample total 16 bytes/sample * 44100 samples per second = 705600 bytes/second - or - 16 bytes/sample * 48000 samples per second = 768000 bytes/second Then, working from your numbers of: - typ. rate : 250nsec/word + PCMCIA/ATA bottle necks = 1.5MB/sec (660nsec/byte) It seems that at "full load" Repeater would be running the media at less than 1/2 of it's potential throughput. I fully admit that I may be missing something... Please correct me if I'm wrong. Do you happen to have a URL for a CF or SM manufacturer with these throughput numbers published? Mark