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P=(V^2)/R rearranging, P*R = V^2 V=(P*R)^(1/2) =(.5*20k)^(1/2) = (10K)^(1/2) =100 V Lots of tube preamps have that much voltage. ----- Original Message ----- From: "Stefan Tiedje" <stefantiedje@googlemail.com> To: <Loopers-Delight@loopers-delight.com> Sent: Monday, September 14, 2009 1:14 AM Subject: Re: FC-7 resistor wattage? > Toby G schrieb: >> I don't know what they were but I can't imagine them being larger than >> 1/2 watt. 1 Watt resistors usually look like a rectangular box. > > Just for fun, calculate the voltage you would need to burn 1/2 watt in a > 20k resistor. I bet you would never want to stomp on such a pedal... > > Stefan > > -- > Les Ondes Mémorielles---------x-- > --_____-----------|-----------|-- > --(_|_ ----|\-----|-----()------- > -- _|_)----|-----()-------------- > ----------()----------TJ Shredder >